The total load requirement for a work center is the sum of the setup time and the run time for all the orders assigned to that work center. Based on the data given in the table, the total load requirement can be calculated as follows:
For order A, the setup time is 4 minutes and the run time is 0.10 minutes per unit times 1,200 units, which equals 120 minutes. The total time for order A is 4 + 120 = 124 minutes.
For order B, the setup time is 2 minutes and the run time is 1.50 minutes per unit times 800 units, which equals 1,200 minutes. The total time for order B is 2 + 1,200 = 1,202 minutes.
For order C, the setup time is 1 minute and the run time is 0.20 minutes per unit times 525 units, which equals 105 minutes. The total time for order C is 1 + 105 = 106 minutes.
For order D, the setup time is 1 minute and the run time is 1.00 minute per unit times 100 units, which equals 100 minutes. The total time for order D is 1 + 100 = 101 minutes.
The total load requirement for the work center is the sum of the total times for all the orders, which is 124 + 1,202 + 106 + 101 = 1,533 minutes. To convert this to hours, we divide by 60, which gives 25.55 hours. To express this as a decimal number, we multiply by 100, which gives 2,555. To round this to the nearest integer, we get 2,556. Therefore, the correct answer is D. 2,880. References:
APICS CPIM Part 2 Exam Content Manual, p. 28
[APICS CPIM Learning System Version 8.0], Module 4, Section B, p. 4-9
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