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Questions # 11:

Consider the Project relation shown in the exhibit as well as the following SQL statement: Which of the following tables shows the Project relation after execution of this SQL statement?

Question # 11

Options:

OptionA

OptionB

OptionC

OptionD

Expert Solution

Questions # 12:

The exhibit shows a table called Housing Relation that relates a unique student identification number with a dormitory building and a room fee for that building. Each building charges only one fee and a student can live in only one building. The key for the Housing Relation is Student_ID.

This table is in which normal form?

Question # 12

Options:

1NF

1NFand2NF

1NF,2NFand3NF

1NF,2NF,3NFandBCNF

Expert Solution

Questions # 13:

What is the highest normal form of the relation(s) shown in the exhibit?

Question # 13

Options:

Third normal form

Second normal form

No normal form

First normal form

Expert Solution

Questions # 14:

What improvement can be made to file-based databases to overcome their limitations?

Options:

Implement a tabular structure.

Gather files in a distributed repository.

Use a hierarchical database file system.

Tightly couple database structure to database application programs.

Expert Solution

Questions # 15:

For the Employee relation shown in the exhibit, which set of column value holds the complete tuple for the employee named James Smith?

Question # 15

Options:

0002, James, Smith

0002, James, Smith, 10-25-76

First_Name, James, Last_Name, Smith

Emp_ID, 0002, First_Name, James, Last_Name, Smith

Expert Solution

Questions # 16:

In which situation would the DBMS use a serial schedule to execute the transactions?

Options:

Concurrent transactions read data from the same data structure.

Concurrent transactions write data to different data structures.

Concurrent transactions read or write the same data structure.

Concurrent transactions read or write from different data structures.

Expert Solution

Questions # 17:

Which of the following definitions applies to all types of databases?

Options:

Data that is stored as tables

Software that manipulates data

Data that is stored in a structured manner

Data records that are stored sequentially in a file

Expert Solution

Questions # 18:

Consider the Registration relation shown in the exhibit. Which of the following SQL statements would return the Registration2 relation from the Registration relation?

Question # 18

Options:

SELECT Course_Code

FROM Registration;

SELECT*FROM

Registration WHERE

Registration_ID = 1003 AND

Registration_ID = 1005;

SELECT*FROM Registration

WHERE Course_Code =‘A4343';

SELECT Registration_ID, Student_ID, First_Name, Last_Name

Expert Solution

Questions # 19:

Consider the Employee relation shown in the exhibit. A database manager wants to set up a view called Emp_Dept that allows users to find employees and their department ID numbers. Which SQL statement will accomplish this?

Question # 19

Options:

CREATE VIEW Emp_Dept AS SELECT

Last_Name, First_Name, Dept_ID FROM

Employee;

UPDATE VIEW Emp_Dept

AS SELECT * FROM

Employee;

UPDATE VIEW Emp_Dept AS SELECT

Last_Name, First_Name, Dept_ID FROM

Employee;

CREATE VIEW Emp_Dept

AS SELECT * FROM

Employee WHERE ID = 0001

AND ID = 0002 AND ID =

0003 AND ID = 0004;

Expert Solution

Questions # 20:

Consider the Information Engineering diagram shown in the exhibit. Building_ID, R_ID, Room_Count and Room_Num are integer numbers, whereas Bldg_Name and Res_Name are represented by variable-length strings with a maximum of 20 characters. Location can be up to 50 characters long, and no building has more than 600 rooms. Which SQL statement best implements the BUILDING relation shown in this diagram?

Question # 20

Options:

CREATE TABLE BUILDING (

Building_ID NOT NULL PRIMARY KEY,

Bldg_Name, Location, Room_Count);

CREATE TABLE BUILDING ( Building_ID NOT NULL PRIMARY

KEY, Bldg_Name, Location, Room_Count, FOREIGN KEY

Building_ID REFERENCES BUILDING (Building_ID));

CREATE TABLE BUILDING (Building_ID

INTEGER NOT NULL PRIMARY KEY,Bldg_Name

VARCHAR (20), Location VARCHAR (50),

CREATE TABLE BUILDING (Building_ID

INTEGER NOT NULL PRIMARY KEY, Bldg_Name

VARCHAR (20), Location VARCHAR (50),

Room_Count INTEGER CHECK (Room_Count >

Room_Count INTEGER CHECK (

-1 And Room_Count < 601));

Room_Count > -1 Or Room_Count < 601));

Expert Solution

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