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Exam Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 All Questions
Exam Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 All Questions

View all questions & answers for the Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 exam

Databricks Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 Question # 1 Topic 1 Discussion

Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 Exam Topic 1 Question 1 Discussion:
Question #: 1
Topic #: 1

A Data Analyst is working on the DataFramesensor_df, which contains two columns:

Which code fragment returns a DataFrame that splits therecordcolumn into separate columns and has one array item per row?

A)

Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 Question 1

B)

Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 Question 1

C)

Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 Question 1

D)

Databricks-Certified-Associate-Developer-for-Apache-Spark-3.5 Question 1


A.

exploded_df = sensor_df.withColumn("record_exploded", explode("record"))

exploded_df = exploded_df.select("record_datetime", "sensor_id", "status", "health")


B.

exploded_df = exploded_df.select(

"record_datetime",

"record_exploded.sensor_id",

"record_exploded.status",

"record_exploded.health"

)

exploded_df = sensor_df.withColumn("record_exploded", explode("record"))


C.

exploded_df = exploded_df.select(

"record_datetime",

"record_exploded.sensor_id",

"record_exploded.status",

"record_exploded.health"

)

exploded_df = sensor_df.withColumn("record_exploded", explode("record"))


D.

exploded_df = exploded_df.select("record_datetime", "record_exploded")


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